Question 474933: I have to figure the dimensions of a fence in a rectangular area, using a 1000 sq ft of my back yard for a dog to run and play in using a Quadratic Equation. Did I calculate this the width correct? Thank you
L = 2W +5
L = length, W = width, P = perimeter, A = area
〖2w〗^2+5w-1000 = 0
A=2, B=5, C=1000
W = (-b±√(b^2-4ac))/2a
W = (-5±√(5^2-4(2)-1000))/(2(2))
W=(-5±√(5^2-4(2)-1000))/(2(2))
W = (-5±√(25-992))/4
W = (-5±√967)/4
W = (-5±√(-5+241.75))/4 = (236.75)/4 = 59.19 OR (-5-241.75)/4 = (-236.75)/4 = -59.19
W = 59.19 yards of fence
Answer by mananth(16949)   (Show Source):
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