# SOLUTION: I am trying to help my daughter witht his quadractic equation. She has to find the root of the quadratic equation in standard form. y=x^2+7x+12 It has been a long time since I've

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Question 432871: I am trying to help my daughter witht his quadractic equation. She has to find the root of the quadratic equation in standard form. y=x^2+7x+12 It has been a long time since I've done this and I need direction to be able to help her with the rest of the problems. Any help would be appreciated!
Found 2 solutions by mananth, Alan3354:
Answer by mananth(12270)   (Show Source):
You can put this solution on YOUR website!
x^2+7x+12
Split the middle term into two such that when the parts are added the give 7x and when multiplied give the product of the first & last term.
x^2+4x+3x+12
x(x+4)+3(x+4)
(x+4)(x+3)
x=-4 ,x=-3

Answer by Alan3354(30993)   (Show Source):
You can put this solution on YOUR website!
find the root of the quadratic equation in standard form.
y=x^2+7x+12
-----------
You can factor it
y=x^2+7x+12 = 0
(x+3)*(x+4) = 0
x = -3, -4
Or use the quadratic equation.
 Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) Quadratic equation (in our case ) has the following solutons: For these solutions to exist, the discriminant should not be a negative number. First, we need to compute the discriminant : . Discriminant d=1 is greater than zero. That means that there are two solutions: . Quadratic expression can be factored: Again, the answer is: -3, -4. Here's your graph: