Question 432871: I am trying to help my daughter witht his quadractic equation. She has to find the root of the quadratic equation in standard form. y=x^2+7x+12 It has been a long time since I've done this and I need direction to be able to help her with the rest of the problems. Any help would be appreciated!
Found 2 solutions by mananth, Alan3354:
Answer by mananth(12270)   (Show Source):
You can put this solution on YOUR website!x^2+7x+12
Split the middle term into two such that when the parts are added the give 7x and when multiplied give the product of the first & last term.
x^2+4x+3x+12
x(x+4)+3(x+4)
(x+4)(x+3)
x=-4 ,x=-3
Answer by Alan3354(30993)  (Show Source):
You can put this solution on YOUR website!find the root of the quadratic equation in standard form.
y=x^2+7x+12
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You can factor it
y=x^2+7x+12 = 0
(x+3)*(x+4) = 0
x = -3, -4
Or use the quadratic equation.
| Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=1 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: -3, -4.
Here's your graph:
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