Question 383609: Hi
Stuck on this, can someone please help
The total surface area S of a closed cone of base radius r cm and perpendicular height h cm is given byS = pir^2 + pi r sqrt(r^2 + h^2). If r and h are each increasing at the rate of 0.25 cm s^-1, find the rate at which S is increasing at the instantwhen r = 3 and h = 4.
Thank You, Answer by Fombitz(13828) (Show Source):