# SOLUTION: Please explain how I may obtain the needed answer. I have (x+3)^2=-25 I thought (X+3)*(x+3)=X^2+6x+9= -25 and moved into quadratic form by adding 25 to both sides. like so, x^

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Please explain how I may obtain the needed answer. I have (x+3)^2=-25 I thought (X+3)*(x+3)=X^2+6x+9= -25 and moved into quadratic form by adding 25 to both sides. like so, x^      Log On

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 Question 320183: Please explain how I may obtain the needed answer. I have (x+3)^2=-25 I thought (X+3)*(x+3)=X^2+6x+9= -25 and moved into quadratic form by adding 25 to both sides. like so, x^2+6x+34=0 then solve for X. At this point I usually give the brain a break and solve using the TI89. Problem is that it keeps telling me false instead of the needed, {-3+5i,-3-5i} Can anyone tell me where I went wrong? ThanksAnswer by stanbon(57342)   (Show Source): You can put this solution on YOUR website!The sum of squares factors as follows: a^2 + b^2 = (a+bi)(a-bi) ================================= (x+3)^2=-25 --- (x+3)^2 + 25 = 0 Factor: [x+3+5i][x+3-5i] = 0 x = -3-5i or x = -3+5i ======================== Not sure what your TI89 is doing. ======================== Cheers, Stan H. ============