SOLUTION: On an xy-coordinate plane, line "L" contains the points (0,0) and (1,2). If line "M" contains the point (0,0) and is perpendicular to line "L", what is an equation of line "M"? Tha

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: On an xy-coordinate plane, line "L" contains the points (0,0) and (1,2). If line "M" contains the point (0,0) and is perpendicular to line "L", what is an equation of line "M"? Tha      Log On

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Question 28003: On an xy-coordinate plane, line "L" contains the points (0,0) and (1,2). If line "M" contains the point (0,0) and is perpendicular to line "L", what is an equation of line "M"? Thanks so much!
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
On an xy-coordinate plane, line "L" contains the points (0,0) and (1,2). If line "M" contains the point (0,0) and is perpendicular to line "L", what is an equation of line "M"? Thanks so much!
SLOPE OF LINE L IS =(2-0)/(1-0)=2
SLOPE OF LINE PERPENDICULAR TO IT IS -1/2
EQN .OF LINE IS
Y-0=(-1/2)(X-0)
2Y+X=0