SOLUTION: The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h = -16t^2 + 104 t, where h is the height in feet and t is the time in

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Question 211164: The height of an object tossed upward with an initial velocity of 104 feet per second is given by the formula h = -16t^2 + 104 t, where h is the height in feet and t is the time in seconds. Find the time required for the object to return to its point of departure
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You are trying to find the time, t, at which the height, h, of the object is zero (initial height) again. I say again because it starts out at h = 0.
So you set h = 0 and solve for t.
-16t%5E2%2B104t+=+0 Factor t from the left side.
t%28-16t%2B104%29+=+0 So...
t+=+0 (Initial condition) or:
-16t%2B104+=+0 and...
-16t+=+-104 Divide both sides by -16.
t+=+6.5seconds.
The oject returns to its point of departure in 6.5 seonds.