# SOLUTION: f(x)=-2x^2+2x+1 the x coordinate of the vertex is? The y coordinate of the vertex is? the equation of the line of symmetry is? the maximum/minimum of the f(x) is (simplified fr

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: f(x)=-2x^2+2x+1 the x coordinate of the vertex is? The y coordinate of the vertex is? the equation of the line of symmetry is? the maximum/minimum of the f(x) is (simplified fr      Log On

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 Question 206086: f(x)=-2x^2+2x+1 the x coordinate of the vertex is? The y coordinate of the vertex is? the equation of the line of symmetry is? the maximum/minimum of the f(x) is (simplified fraction)? Answer by nerdybill(7003)   (Show Source): You can put this solution on YOUR website!f(x)=-2x^2+2x+1 . Axis of symmetry = -b/2a = -2/(2*(-2)) = -2/-4 = 1/2 Therefore, the equation of the line of symmetry is: x = 1/2 . Plug above back into: f(x)=-2x^2+2x+1 f(1/2)=-2(1/2)^2+2(1/2)+1 f(1/2)=-2(1/4)+1+1 f(1/2)=-(1/2)+2 f(1/2)=-(1/2)+(4/2) f(1/2)= 3/2 . the x coordinate of the vertex is? 1/2 The y coordinate of the vertex is? 3/2 the equation of the line of symmetry is? x= 1/2 the MAXIMUM of the f(x) is (simplified fraction)? 3/2