SOLUTION: {{{f(x)=25-x^2}}}The instructions say to sketch the graph of the quadratic function. Identify the vertex & x-intercept(s). I seem to be lost. I know to 1st factor it (I don't belie

You can put this solution on YOUR website!

This is the difference between two perfect squares.

In your case a=5 and b=x

Let f(x)=0

Use the zero product property and set each parenthesis = 0.
5+x=0
-5+5+x=0-5
x=-5
and
5-x=0
-5-x=0-5
-x=-5
-x/-1=-5/-1
x=5
Those are your x intersepts:(5,0),(-5,0).
Let x=0 and find your y intersept:
y=25-0^2
y=25
Now you can plot your y-intersept:(0,25)
This also happens to be the vertex of the parabola in this case.
The fact that x^2 is negative tells you that the parabola opens upside down.