SOLUTION: I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 + 112t. The velocity is 112 ft/s, so I need to solve it as 16t^2 + 112t = 180

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 + 112t. The velocity is 112 ft/s, so I need to solve it as 16t^2 + 112t = 180      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 50420This question is from textbook
: I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 + 112t. The velocity is 112 ft/s, so I need to solve it as 16t^2 + 112t = 180This question is from textbook

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 + 112t. The velocity is 112 ft/s, so I need to solve it as 16t^2 + 112t = 180
16T^2+112T-180=0...DIVIDE WITH 4
4T^2+28T-45=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
T=[-28+SQRT{28^2-4*4*(-45)}]/8=1.3477