SOLUTION: Find the equation of the axis of symmetry for the following parabola y = x^2 - 6x + 7

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Question 4271: Find the equation of the axis of symmetry for the following parabola y = x^2 - 6x + 7
Answer by rapaljer(4551) About Me  (Show Source):
You can put this solution on YOUR website!
For a graph of a parabola that opens up or down in the form
y+=+ax%5E2+%2B+bx+%2B+c
the vertex and therefore the axis of symmetry is always at
x+=+%28-b%29%2F2a. This formula comes from the quadratic formula!! x=%28-b%2B-sqrt+%28b%5E2-4ac%29%29%2F%282a%29

Therefore, the axis of symmetry for
y+=+x%5E2+-+6x+%2B+7 where a=1, b=-6, and c=7
is x=%28-%28-6%29%29%2F%282%281%29%29 or x=3

R^2 at SCC