SOLUTION: I have to find all the values of b in the following equation that will give one or more real number solutions. Can you please help me with this? 3x^2 + bx - 3 = 0 Thanks!

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Question 41070: I have to find all the values of b in the following equation that will give one or more real number solutions. Can you please help me with this?
3x^2 + bx - 3 = 0
Thanks!
Answer by stanbon(48568) About Me  (Show Source):
You can put this solution on YOUR website!
I have to find all the values of b in the following equation that will give one or more real number solutions. Can you please help me with this?
3x^2 + bx - 3 = 0
For that to happen the discriminant must be greater than
or equal to zero.
Discriminant = b^2-4*3*(-3)
b^2+36>=0
b^2>=-36
This is true for any Real Number value of "b".
Cheers,
Stan H.