SOLUTION: Good Afternoon, I was hoping someone could assist me as I work through the following problem. If you could be so kind as to show all of the steps you would utilize to solve the pro

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Good Afternoon, I was hoping someone could assist me as I work through the following problem. If you could be so kind as to show all of the steps you would utilize to solve the pro      Log On


   

Question 362551: Good Afternoon, I was hoping someone could assist me as I work through the following problem. If you could be so kind as to show all of the steps you would utilize to solve the problem below, I would greatly appreciate it!
11.3, #5,
Directions: Find the axis of symmetry of the parabola defined by the given quadratic function.
f(x)=(x+2)^2+8=x
Thank you so much!


Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I'm going to assume that this is your function.
f%28x%29=%28x%2B2%29%5E2%2B8
The quadratic is already in vertex form, y=a%28x-h%29%5E2%2Bk
where (h,k) is the vertex.
Comparing,
(h,k)=(-2,8)
The vertex lies on the axis of symmetry, x=-2.
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