You can
put this solution on YOUR website!It would help if you put more time into copying the question correctly and less time crying.
Notice how squared is correctly written. Notice how 1) appears by enclosing the problem in three "{" and three "}" curly braces. Next to the p key
1)
2) y=-x^2+2x-1
The rules of the website say
One problem per submission.
No similar problems and
Limit of 4 submissions daily
You broke two of the rules already.
One and two are similar and are two problems.
Whereas A and B can be considered one problem
Here is the solution to 1)
The determinant tells how many x roots there are.
See description below
vertex lowest point (5/2, -1/4) slightly below the x axis
the x of the vertex is -b/2a find that and plug it in to find y
-(-)5/2(1)=5/2
plug 5/2 for x and get -1/4 for y in
y=x^2-5x+6
y=5/2^2-5*5/2+6
y=25/4-25/2+24/4
y=(25-50+24)/4
y=-1/4
BTW y=x^2-5x+6 can be factored into y=(x-3)(x-2)
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=1 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: 3, 2.
Here's your graph:
 |
You can
put this solution on YOUR website!without drawing the graph of the given equation determine
A) how many x-intercepts the parabola has
ANS: There are three options (i) 0 intercepts; (ii) 1 intercept. (iii) 2 intercepts. The way to determine this is by the discriminant. It is
If D < 0, then 0 intercepts
If D = 0, then 1 intercept
If D > 1, then 2 intercepts
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B) whether its vertex lies above or below or on the x-axis.
show your work.
1) y=x^2 - 5x +6
D > 0, so 2 intercepts
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2) y= -x^2 + 2x -1
D = 0, so 1 intercept
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