SOLUTION: write an equation for the following function in vertex form: then it shows a parabola, the vertex is (2,1) and the point is (-2,5)

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: write an equation for the following function in vertex form: then it shows a parabola, the vertex is (2,1) and the point is (-2,5)      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   


Question 183995: write an equation for the following function in vertex form:
then it shows a parabola,
the vertex is (2,1) and the point is (-2,5)

Answer by stanbon(57984) About Me  (Show Source):
You can put this solution on YOUR website!
write an equation for the following function in vertex form:
then it shows a parabola,
the vertex is (2,1) and the point is (-2,5)
------------------------------------------------
Form (x-h)^2 = 4p(y-k)
--------------------------
(h,k) is the vertex (2,1)
substitute to get:
(x-2)^2 = 4p(y-1)
------------------------
Let y = 5 when x = -2
(-2-2)^2 = 4p(5-1)
16 = 4p(4)
p = 1
----------------
Equation:
(x-2)^2 = 4(y-1)
========================
Cheers,
Stan H.