SOLUTION: The sum of a number, five-fourths of the number, and a third of the number is one hundred fifty-five. Find the number. Here's what I have x + x + 5/4 + x + 1/3 + x =155 4x + 5

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The sum of a number, five-fourths of the number, and a third of the number is one hundred fifty-five. Find the number. Here's what I have x + x + 5/4 + x + 1/3 + x =155 4x + 5      Log On


   

Question 127308: The sum of a number, five-fourths of the number, and a third of the number is one hundred fifty-five. Find the number.
Here's what I have
x + x + 5/4 + x + 1/3 + x =155
4x + 5/4 + 1/3 =155
5/4 + 1/3= 1 7/12
4x = 1 7/12
?????
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You're on the right track, but "five-fourths of the number" does not translate to x%2B5%2F4. It translates to %285%2F4%29x where the 5%2F4 is multiplied by x. The same applies to the statement "third of the number "


So our equation should look like this:

x+%2B+%285%2F4%29x+%2B+%281%2F3%29x+=155



%2812%29%28x%2B%285%2F4%29x%2B%281%2F3%29x%29=%2812%29%28155%29 Multiply both sides by the LCD of 12 (the LCD is the LCM of the denominators). This will eliminate the fractions (note: if you need help with finding the LCM, check out this solver)



12x%2B15x%2B4x=1860 Distribute and multiply the LCM to each side



31x=1860 Combine like terms on the left side


x=%281860%29%2F%2831%29 Divide both sides by 31 to isolate x



x=60 Divide

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Answer:
So our answer is x=60


So the number is 60