You can
put this solution on YOUR website!Let x = first number
x+6 = second number
Let y = product of the numbers
y = x(x+6)
Graph the equation of this parabola, and find the lowest value of y, which is the vertex of the parabola. Algebraically, the vertex will always be at
(where a=1, b=6 as in the quadratic formula!) so
. Also halfway between the x intercepts, which would be at x=0 and x= -6. The minimum value of the product of the numbers would be
.
R^2 at SCC
