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A ball is tossed from a window that is 10 feet off the ground. The height, h (in feet), of the ball at any time, t (in seconds), is given by the equation h = - 16 t^2 + 12x + 10. What is the maximum height (in feet) that the ball will reach?
h = - 16 t^2 + 12x + 10
This is an equation of a parabola that opens downwards (function has a maximum)
Its standard form: y=(x-h)^2+k, (h,k)=(x,y) coordinates of vertex, k=maximum value
complete the square
maximum height that the ball will reach=12.25 ft