Question 5053: Q. Prove the following identity: 1 divided by 1+cosx = 1/sin^2x - 1/sinxtanx
I am at the dead end but these are my steps:
R.S.
1 divided by(sinx)(sinx)-1 divided by (sinx)(sinx/cosx)=
sin^2x+cos^2x divided by sin^2x - sin^2x+cos^2xdivided by (sin^2x/cosx)=
(sinx)(sinx)+(cosx)(cos)divided by (sinx)(sinx) - (sinx)(sinx) + (cosx)(cosx)(cosx)divided by (sinx)(sinx)=
sin^2x + cos^2x - sin^2x + cos^2x(cosx) divided by (sinx)(sinx)=
and here either
1 - cosx divided by sin^2x
or
2cos^2x(cosx)divided by sin^2x
--------
thanks mmm
Answer by longjonsilver(2297)   (Show Source):
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