# SOLUTION: find the value of k so that the equation 5x^2-8x+k=0 will have roots whose product is equal to 2/3?

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 Question 495248: find the value of k so that the equation 5x^2-8x+k=0 will have roots whose product is equal to 2/3? Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website! find the value of k so that the equation 5x^2-8x+k=0 will have roots whose product is equal to 2/3? ---- Roots are [8 +- sqrt(64 - 4*5*k)]/10 x = (4/5)+sqrt(64-20k)/10 and x = (4/5)-sqrt(64-20k)]/10 ---- Their product = (4/5)^2 - [(64-20k)/10] ---- Solve for "k": (4/5)^2 - [(64-20k)/10] = 2/3 (16/25) - 6.4 + 2k = 2/3 0.64-6.4+2k = 2/3 2k -5.76 = 2/3 k - 2.88 = 1/3 k = 3.2133 =============== Cheers, Stan H.