You can put this solution on YOUR website!
L = length
W = width
width is 2/3 of the length.
this means that W = 2/3 * L
area of the rectangle is 216 square meters.
area of a rectangle is equal to L * W
L*W = 216
since W = 2/3 * L, then substitute for W to get:
L * (2/3 * L) = 216
simplify to get:
2/3 * L^2 = 216
multiply both sides of the equation by 3/2 to get:
L^2 = 216 * 3/2 = 324
take square root of both sides of this equation to get:
L = +/- 18
Since L can't be negative, then L = 18
W = 2/3 * L = 2/3 * 18 = 12
L = 18
W = 12
12 * 18 = 216
first problem solved.
problem number 2:
The width and length of a rectangle are consecutive odd integers.If the length is increased by five feet,the area of the resulting rectangle is 60 square feet.
Find the dimensions and the area of the original rectangle.
L = length of rectangle
W = width of rectangle
length and width are consecutive odd integers.
Let L = W + 2
This means that, if W is an odd integer, then L is the next consecutive odd integer.
if length is increased by 5 feet, the area of the rectangle becomes 60 square feet.
area of rectangle is L*W
if you increase L by 5, then the formula becomes:
(L+5)*W = 60
Since L = W + 2, you can substitute in this equation to get:
(W+7)*W = 60
Simplify to get:
W^2 + 7W = 60
subtract 60 from both sides of this equation to get:
W^2 + 7W - 60 = 0
factor this quadratic equation to get:
(W+12) * (W-5) = 0
This makes W = -12 or W = 5
W can't be negative, so the only viable answer is W = 5
Since L is equal to W + 2, you get L = 7
The original dimensions of the rectangles are L = 7 and W = 5
The original area of the rectangle is 7*5 = 35
Add 5 to the length and you get 12*5 = 60, satisfying the requirements of the problem.