# SOLUTION: please help me solve each system of equation 1.) y=3x-4 2.) x-2y=-14 3.) x+2y=4 4.) 3x-y=2 y=-2x+1 y+2x=4 2x+y=-1 y=2x-5 and whats the soluti

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: please help me solve each system of equation 1.) y=3x-4 2.) x-2y=-14 3.) x+2y=4 4.) 3x-y=2 y=-2x+1 y+2x=4 2x+y=-1 y=2x-5 and whats the soluti      Log On

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 Click here to see ALL problems on Quadratic Equations Question 184230: please help me solve each system of equation 1.) y=3x-4 2.) x-2y=-14 3.) x+2y=4 4.) 3x-y=2 y=-2x+1 y+2x=4 2x+y=-1 y=2x-5 and whats the solution??Answer by jeselle(2)   (Show Source): You can put this solution on YOUR website!by substitution: 1.) y=3x-4 y=-2x+1 simply substitute the value of y in the second equation to the first -2x+1=3x-4 -2x-3x=-4-1 -5x=-5 (divide both sides by -5) x=1 by elimination -3x+y=-4 2x+y=1 (subtract so that the sign of the subtrahend will be the opposite) -3x+y=-4 -1(2x+y=1)-1 -3x+y=-4 -2x-y=-1 then add -5x=-5 x=1 do the same with the others and try practicing.^^