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==section input A Quadratic equation would looks like {{{ax^2+bx+c = 0 }}} a = *[input a=1] where "a" can not be 0 b = *[input b=4] c = *[input c=2] And they will ask you to solve for x. Most of the time there will be 2 solutions for x. ==section solution $b {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} {{{x = (-$b + sqrt($b^2-4*$a*$c))/(2*$a)) }}} OR {{{x = (-$b - sqrt($b^2-4*$a*$c))/(2*$a) }}} {{{x = (*[assign k=-$b] $k + sqrt(*[assign d=$b*$b] $d-*[assign m=4*$a*$c] $m))/(*[assign 2a=2*$a] $2a) }}} OR {{{x = (*[assign k=-$b] $k - sqrt(*[assign d=$b*$b] $d-*[assign m=4*$a*$c] $m))/(*[assign 2a=2*$a] $2a)) }}} {{{x = (*[assign k=-$b] $k + sqrt(*[assign v=$d-$m] $v))/(*[assign 2a=2*$a] $2a)) }}} OR {{{x = (*[assign k=-$b] $k - sqrt(*[assign v=$d-$m] $v))/(*[assign 2a=2*$a] $2a)) }}} {{{x = (*[assign k=-$b] $k + *[assign h=($v)^(0.5)] $h) /(*[assign 2a=2*$a] $2a)) }}} OR {{{x = (*[assign k=-$b] $k - *[assign h=($v)^(0.5)] $h) /(*[assign 2a=2*$a] $2a)) }}} {{{x = *[assign p=$k+$h] $p/($2a)] }}} OR {{{x = *[assign w=$k-$h] $w/($2a)] }}} {{{x = *[assign l=$p/$2a] $l }}} OR {{{x = *[assign j=$w/$2a] $j }}} ==section output ==section check a=1 b=2 c=1 x=-1