SOLUTION: Explain why x^2+bx-c=0 must have one positive real and one negative real solution when b and c are real numbers and c>0 .
For what values of b will x^2+bx+1=0have real solutions
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Explain why x^2+bx-c=0 must have one positive real and one negative real solution when b and c are real numbers and c>0 .
For what values of b will x^2+bx+1=0have real solutions
Log On
Question 995840: Explain why x^2+bx-c=0 must have one positive real and one negative real solution when b and c are real numbers and c>0 .
For what values of b will x^2+bx+1=0have real solutions? Clearly explain the reasoning you followed to reach your conclusion Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! The first part is wrong. That cannot be justified. An example was already given a few minutes ago.
Use the discriminant for the second question. --- given equation; --- the discriminant, using a=1 and c=1;
- --- discriminant must be non-zero for the original quadratic equation to have real solutions.
(