SOLUTION: Find the values for x where X^2 - 12 < 3x + 6.

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Question 995396: Find the values for x where X^2 - 12 < 3x + 6.

Answer by ikleyn(52790) About Me  (Show Source):
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Find the values for x where X^2 - 12 < 3x + 6.
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x%5E2+-+12 < 3x+%2B+6.

x%5E2+-+3x+-+18 < 0.

Factor the quadratic polynomial in the left side:

x%5E2+-+3x+-+18 = x%2B3%29%2A%28x-6%29.

Thus your inequality is equivalent to

%28x%2B3%29%2A%28x-6%29 < 0.

The solution is the interval  -3 < x < 6.

Answer.  The solution is the interval  (-3, 6).