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solve the equation for x
2(x-5)^2 =3
2(x-5)^2 = 3
2(x^2-10x+25) = 3
2x^2-20x+50-3 = 0
2x^2-20x+47 = 0
compare with std form we get a= 2 , b= -20 and c = 47
substituting for a,b and c we get ,
x = -(-20)+-sq.rt (-20)^2-4.2.47/2.2
= 20 +-sq.rt 400-376/4
= 20+-sq.rt 24/4
= 20+-2.sq.rt6/4
= 2(10+-sq.rt 6)/4
= (10+-sq.rt 6)/2