SOLUTION: Complete the square on the following quadratic x2+14x+9=0 what value is added to both sides of the equation.

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Question 981399: Complete the square on the following quadratic
x2+14x+9=0
what value is added to both sides of the equation.


Found 3 solutions by Boreal, richwmiller, rothauserc:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+14x+9=0
x^2+14x=-9
take half of the x term and square it, adding that number to both sides of the equation.
x^2+14x+49= -9+49
(x+7)^2=40
x+7= sqrt (40)=+/- 2 sqrt 10
x= -7 +/- 2 sqrt (10)

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: COMPLETING THE SQUARE solver for quadratics
Read this lesson on completing the square by prince_abubu, if you do not know how to complete the square.
Let's convert 1x%5E2%2B14x%2B9=0 to standard form by dividing both sides by 1:
We have: 1x%5E2%2B14x%2B9=0. What we want to do now is to change this equation to a complete square %28x%2Bsomenumber%29%5E2+%2B+othernumber. How can we find out values of somenumber and othernumber that would make it work?
Look at %28x%2Bsomenumber%29%5E2: %28x%2Bsomenumber%29%5E2+=+x%5E2%2B2%2Asomenumber%2Ax+%2B+somenumber%5E2. Since the coefficient in our equation 1x%5E2%2Bhighlight_red%28+14%29+%2A+x%2B9=0 that goes in front of x is 14, we know that 14=2*somenumber, or somenumber+=+14%2F2. So, we know that our equation can be rewritten as %28x%2B14%2F2%29%5E2+%2B+othernumber, and we do not yet know the other number.
We are almost there. Finding the other number is simply a matter of not making too many mistakes. We need to find 'other number' such that %28x%2B14%2F2%29%5E2+%2B+othernumber is equivalent to our original equation 1x%5E2%2B14x%2Bhighlight_green%28+9+%29=0.


The highlighted red part must be equal to 9 (highlighted green part).

14%5E2%2F4+%2B+othernumber+=+9, or othernumber+=+9-14%5E2%2F4+=+-40.
So, the equation converts to %28x%2B14%2F2%29%5E2+%2B+-40+=+0, or %28x%2B14%2F2%29%5E2+=+40.

Our equation converted to a square %28x%2B14%2F2%29%5E2, equated to a number (40).

Since the right part 40 is greater than zero, there are two solutions:

system%28+%28x%2B14%2F2%29+=+%2Bsqrt%28+40+%29%2C+%28x%2B14%2F2%29+=+-sqrt%28+40+%29+%29
, or

system%28+%28x%2B14%2F2%29+=+6.32455532033676%2C+%28x%2B14%2F2%29+=+-6.32455532033676+%29
system%28+x%2B14%2F2+=+6.32455532033676%2C+x%2B14%2F2+=+-6.32455532033676+%29
system%28+x+=+6.32455532033676-14%2F2%2C+x+=+-6.32455532033676-14%2F2+%29

system%28+x+=+-0.675444679663241%2C+x+=+-13.3245553203368+%29
Answer: x=-0.675444679663241, -13.3245553203368.

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 14x + 9 = 0
subtract 9 from both sides of =
x^2 + 14x = -9
divide x coefficient by 2 and square it, then add 49 to both sides of =
x^2 + 14x + 49 = 40
factor polynomial
(x + 7) * (x + 7) = 40
take square root of both sides of =
x + 7 = 2 * square root of 10
x = 2 * square root(10) - 7 = −0.68
x = 2 *(-square root(10)) - 7 = −13.32
x = −0.68 or x = −13.32
NOTE. we added 49 to both sides of the equation