SOLUTION: These quadratics are killing me. Can you help me with this one?
(x+2)(x+3)=(x+7)(x-4)
I have multiplied and got x^2+6=X^2-28
but where do I go from here? Should I subtract 6 f
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Quadratic Equations and Parabolas
-> SOLUTION: These quadratics are killing me. Can you help me with this one?
(x+2)(x+3)=(x+7)(x-4)
I have multiplied and got x^2+6=X^2-28
but where do I go from here? Should I subtract 6 f
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Question 971190: These quadratics are killing me. Can you help me with this one?
(x+2)(x+3)=(x+7)(x-4)
I have multiplied and got x^2+6=X^2-28
but where do I go from here? Should I subtract 6 from both sides or add 28 to each side? Answer by josgarithmetic(39617) (Show Source):
(