SOLUTION: x+3=sq.root x+15
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Question 96897
:
x+3=sq.root x+15
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
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Does your problem look like this:
Start with the given equation
Square both sides
Foil
Get all terms to one side
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve
( notice
,
, and
)
Plug in a=1, b=5, and c=-6
Square 5 to get 25
Multiply
to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this
solver
)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or
Lets look at the first part:
Add the terms in the numerator
Divide
So one answer is
Now lets look at the second part:
Subtract the terms in the numerator
Divide
So another answer is
So our possible solutions are:
or
Let's check them:
Let's check the solution x=-6
Start with the given equation
Plug in x=-6
Combine like terms
Take the square root of 9. Since this is not true, x=-6 is not a solution (it's extraneous)
Let's check the solution x=1
Start with the given equation
Plug in x=1
Combine like terms
Take the square root of 16. Since this is true, x=1 is a solution
So our only solution is