SOLUTION: Graph the parabola and find its vertex y=x^2-6x+1

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Question 968620: Graph the parabola and find its vertex
y=x^2-6x+1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Graph the parabola and find its vertex
y=x^2-6x+1
complete the square:
y=(x^2-6x+9)-9+1
y=(x-3)^2-8
vertex: (3, -8)
see graph below:
+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2Cx%5E2-6x%2B1%29+