SOLUTION: I need help finding the parabola of g(x)=1/2(x-2)^2-4. I know the vertex is (-2,4) but the graph shows (2-2sqrt2,0) and 2+2sqrt2,0) also (0,-2).

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Question 964991: I need help finding the parabola of g(x)=1/2(x-2)^2-4. I know the vertex is (-2,4) but the graph shows (2-2sqrt2,0) and 2+2sqrt2,0) also (0,-2).
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!
Careful how to think about how standard form works.

y=a(x-h)^2+k has a vertex (h,k).

Find the y intercepts by setting x=0 and solve for y.
Find the x intercepts by setting y=0 and solve for x, which is simple to do because your equation is in standard form.

Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!

I need help finding the parabola of g(x)=1/2(x-2)^2-4. I know the vertex is (-2,4) but the graph shows (2-2sqrt2,0) and 2+2sqrt2,0) also (0,-2).

y is 0 on the x-axis, so () and () are the x-intercepts
x is 0 on the y-axis, so () is the y-intercept
You've already determined the coordinates of the vertex, so you have what's needed to form the equation of the parabola