SOLUTION: 1. Determine the domain and range for f(x)=3+√(x-5). 2. Given that f(x)=3+√(x-5) and g(x)=tan x. determine fog(x).

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 1. Determine the domain and range for f(x)=3+√(x-5). 2. Given that f(x)=3+√(x-5) and g(x)=tan x. determine fog(x).       Log On


   



Question 956406: 1. Determine the domain and range for f(x)=3+√(x-5).
2. Given that f(x)=3+√(x-5) and g(x)=tan x. determine fog(x).

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29%22%22=%22%223%2Bsqrt%28x-5%29.

f(x) and y are the same thing. So write it as:

y%22%22=%22%223%2Bsqrt%28x-5%29

What's under the square root, x-5, cannot be negative so it must be
greater than or equal to 0, so we have:

x-5%22%22%3E=%22%220
x%22%22%3E=%22%225}

So the domain is the set of all x-values greater than or equal to 5.

{x | x ≥ 5} or in interval notation: [5,infinity)

Since the square root sqrt%28x-5%29 is never negative we can write

sqrt%28x-5%29%22%22%3E=%22%220

We can add 3 to both sides to make the right side of f(x) above:

3%2Bsqrt%28x-5%29%22%22%3E=%22%223

And since  

y%22%22=%22%223%2Bsqrt%28x-5%29

y%22%22%3E=%22%223%29

So the range is the set of all y-values greater than or equal to 3.

{y | y ≥ 3} or in interval notation: [3,infinity).  
 
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f∘g(x) = f%28g%28x%29%5E%22%22%29, so we substitute the right side of
g(x) for x in the right side of f(x).

f∘g(x)%22%22=%22%22f%28g%28x%29%5E%22%22%29%22%22=%22%22%22%22=%22%223%2Bsqrt%28tan%28x%29-5%29.

Edwin