SOLUTION: Please help me. Solve the following equations by completing the square. Leave your answer in surd form. 1) 2x²-6x+1=0 2) 3x²-6x-1=0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please help me. Solve the following equations by completing the square. Leave your answer in surd form. 1) 2x²-6x+1=0 2) 3x²-6x-1=0      Log On


   

Question 955639: Please help me.
Solve the following equations by completing the square. Leave your answer in surd form.
1) 2x²-6x+1=0
2) 3x²-6x-1=0
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
1)
2x%5E2-6x%2B1=0
%282x%5E2-6x%2B_%29=-1
2%28x%5E2-3x%2B%283%2F2%29%5E2%29=-1
%28x%5E2-3x%2B%283%2F2%29%5E2%29-%283%2F2%29%5E2=-1%2F2
%28x-3%2F2%29%5E2=9%2F4-1%2F2
%28x-3%2F2%29%5E2=7%2F4
%28x-3%2F2%29=+sqrt%287%2F4%29
%28x-3%2F2%29=sqrt%287%29%2F2
x=sqrt%287%29%2F2%2B3%2F2 or x=-sqrt%287%29%2F2%2B3%2F2
x=%281%2F2%29%28sqrt%287%29%2B3%29 or x=-%281%2F2%29%28sqrt%287%29%2B3%29


2)
3x%5E2-6x-1=0
3x%5E2-6x=1
3%28x%5E2-2x%29=1
%28x%5E2-2x%29=1%2F3
%28x%5E2-2x%2B_%29-_=1%2F3
%28x%5E2-2x%2B1%29-1=1%2F3
%28x-1%29%5E2=1%2F3%2B1
%28x-1%29%5E2=4%2F3
%28x-1%29=sqrt%284%2F3%29
%28x-1%29=sqrt%284%29%2Fsqrt%283%29
x-1=2%2Fsqrt%283%29
x=1%2B2%2Fsqrt%283%29 or x=1-2%2Fsqrt%283%29