Question 948324: Need to know info:
Use the following equation to answer the question: f(x)=−0.08x^2+1.6x+3 and assume that an arrow is being shot and the arch represents the flight path. But, the height the arrow leaves the archer's bow is 3 yards above ground level and was aimed towards a target that is also 3 yards tall
Question:
1.) How long did it take the arrow to leave the bow and hit the target?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Use the following equation to answer the question:
f(x)=−0.08x^2+1.6x+3 and assume that an arrow is being shot and the arch represents the flight path.
But, the height the arrow leaves the archer's bow is 3 yards above ground level and was aimed towards a target that is also 3 yards tall
:
Since it departs and arrives at the same height, we can ignore the 3, makes it easy to solve
.08x^2 + 1.6x = 0
Factor out -x
-x(.08x - 1.6) = 0
.08x = 1.6
x = 1.6/.08
x = 20 seconds to hit the target
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