SOLUTION: find 3 consecutive positive even integers such that the sum of the squares of the first and second integers is equal to the square of the third integer plus 48

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Question 946223: find 3 consecutive positive even integers such that the sum of the squares of the first and second integers is equal to the square of the third integer plus 48
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%28N-2%29%5E2%2BN%5E2=%28N%2B2%29%5E2%2B48
N%5E2-4N%2B4%2BN%5E2=N%5E2%2B4N%2B4%2B48
N%5E2-8N-48=0
%28N-12%29%28N%2B4%29=0
Only the positive solution is needed.
N-12=0
N=12
So the integers are 10,12, and 14.