SOLUTION: h(x)= -3x^2 and h (x)= -sqrt x-1 I am needing to solves and have graphs along with there domains and range. I am very perplexed on how to even do these let a long put them i

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: h(x)= -3x^2 and h (x)= -sqrt x-1 I am needing to solves and have graphs along with there domains and range. I am very perplexed on how to even do these let a long put them i      Log On


   

Question 944001: h(x)= -3x^2
and
h (x)= -sqrt x-1
I am needing to solves and have graphs along with there domains and range. I am very perplexed on how to even do these let a long put them in writing.
Please HELP
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
The two definitions for h(x) are not equal to each-other; do you WANT them to be set as equal, and then to solve for x? Also, the second definition is ambiguous, so helping with it is less reliable. What is it? -sqrt%28x-1%29? -sqrt%28x%29-1? -%28sqrt%28x%29-1%29?

(Some discussion given privately)
..

Here is what your second function looks like when surrounded by the triple braces rendering tags:
h%28x%29=-sqrt+x-1
which is just as ambiguous as without the rendering tags.
WHAT FUNCTION DO YOU REALLY HAVE FOR THIS?