SOLUTION: Application problem. A square and rectangle have the same area. The length of the rectangle is five inches more than twice the length of the side of the square. Find the length

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Question 942836: Application problem.
A square and rectangle have the same area. The length of the rectangle is five inches more than twice the length of the side of the square. Find the length of the side of the square.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A square and rectangle have the same area.
The length of the rectangle is five inches more than twice the length of the side of the square.
Find the length of the side of the square.
:
Seems like we have to have something on the width of the rectangle as related to x,
anyway, full speed ahead
:
let x = the length of the square
then
(2x+5) = the length of the rectangle
and
let w = the width of the rectangle
:
w(2x+5) = x^2
w = x%5E2%2F%28%282x%2B5%29%29
Hopefully we are dealing in integers, the only positive integer solution
x = 10, w = 4 or it could have been (x-6) is the width
See if that works
x^2 = 100
the rectangle
4(2(10)+5) = 4(20+5) = 100
:
10 inches is the side of the square