SOLUTION: given f(t) = 2t+3, does the equation have no solution, one solution, or an infinate number of solutions? f(t) + 1 = f(t+1)

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Question 939220: given f(t) = 2t+3, does the equation have no solution, one solution, or an infinate number of solutions?
f(t) + 1 = f(t+1)
Found 3 solutions by TimothyLamb, Fombitz, josgarithmetic:
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
given:
f(t) = 2t + 3
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f(t) + 1 = f(t+1)
2t + 3 + 1 = 2(t + 1) + 3
2t + 4 = 2t + 2 + 3
2t + 4 = 2t + 5
4 = 5
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answer:
no solution
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Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%28t%29=2t%2B3
f%28t%2B1%29=2%28t%2B1%29%2B3=2t%2B2%2B3=2t%2B5
So,
f%28t%29%2B1=f%28t%2B1%29
2t%2B3=2t%2B5
3=5
No solutions.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The statement is a function, a polynomial, specifically a linear function, and represents a line. How many points are on a line?

The next equation can be formed as f(t+1)=f(t)+1. Guessing that f is the same function given earlier, 2%28t%2B1%29%2B3=2t%2B3%2B1,
2t%2B2%2B3=2t%2B4
5=4, FALSE. That equation has no solution.