SOLUTION: Question 4 Given y = x^2-x-6 a) Determine the x-intercepts. b) Determine the turning point.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Question 4 Given y = x^2-x-6 a) Determine the x-intercepts. b) Determine the turning point.       Log On


   

Question 924017: Question 4 Given y = x^2-x-6
a) Determine the x-intercepts.

b) Determine the turning point.

d) Determine the y-intercept.

e) Hence, or otherwise, sketch the graph of y = x^2-x-6

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
y = x^2 -x -6
factor this equation
y = (x-3)(x+2)
a) x intercepts are 3 and -2
b) turning point is the vertex of this parabola, x part of vertex is
x = -b/2a = 1/2 = 0.5
y = 1/4 - 1/2 -6 = -6.25
turning point is (0.5, -6.25
d) y intercept is -6
graph of this parabola is
+graph%28+300%2C+200%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2+-x+-6+%29+