SOLUTION: h(x)=2x^2+6x+25 Find the vertex and axis of symmetry.

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Question 913239: h(x)=2x^2+6x+25
Find the vertex and axis of symmetry.
Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
h(x)=2x^2+6x+25
h(x)=2(x + 3/2)^2 - 9/2 + 25
h(x)=2(x + 3/2)^2 + 41/2
V(-3/2, 20.5)
axis of symmetry: x = -3/2

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to vertex form,
h%28x%29=2x%5E2%2B6x%2B25
h%28x%29=2%28x%5E2%2B3x%29%2B25
h%28x%29=2%28x%5E2%2B3x%2B%283%2F2%29%5E2%29%2B25-2%283%2F2%29%5E2%29
h%28x%29=2%28x%2B3%2F2%29%5E2%2B50%2F2-9%2F2
h%28x%29=2%28x%2B3%2F2%29%5E2%2B41%2F2
The vertex is (-3%2F2,41%2F2).
The axis of symmetry is x=-3%2F2
The parabola opens upwards.