SOLUTION: How do I graph f(x)=-2/3(x+2)^2-1 I found the vertex which is (-2,-1). I also need to find the x intercept and y intercept and explain the transformation

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: How do I graph f(x)=-2/3(x+2)^2-1 I found the vertex which is (-2,-1). I also need to find the x intercept and y intercept and explain the transformation      Log On


   

Question 911008: How do I graph f(x)=-2/3(x+2)^2-1
I found the vertex which is (-2,-1). I also need to find the x intercept and y intercept and explain the transformation
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=-%282%2F3%29%28x%2B2%29%5E2-1
(parentheses around 2/3 to make rendering show the actual function you want).

The function is in standard form. The x-intercepts happen for f%28x%29=0, easily solved, since you already have f in standard form. Do this!

The y-intercept occurs for x=0; so just evaluate f%280%29.


graph%28300%2C300%2C-5%2C5%2C-5%2C5%2C-%282%2F3%29%28x%2B2%29%5E2-1%29

You should be able to understand the situation of the x-intercepts from the algebraic solving process of finding those values.