SOLUTION: I've racked my brain for hours & I still don't know where to begin on this problem: A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions
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Question 90931This question is from textbook Beginning Al
: I've racked my brain for hours & I still don't know where to begin on this problem: A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30 ft by 40 ft. the total area, garden plus walkway, is to be 1800 ft^2. What must be the width of the walkway to the nearest thousandth?
Thank you. This question is from textbook Beginning Al
If we let x be the width of the path, notice there are 2 x-values per side. So we add 2x to 40 to get 40+2x. This is the total length of the side that contains 40 feet.
Also, this means we add 2x to 30 to get 30+2x. This is the total length of the side that contains 30 feet.
Start with the general area function:
Plug in (this is the total area)
Plug in and
Foil
Subtract 1800 from both sides
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=4, b=140, and c=-600
Square 140 to get 19600
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 4 to get 8
So now the expression breaks down into two parts
or
Now break up the fraction
or
Simplify
or
So these expressions approximate to
or
So our possible solutions are:
or
Since a negative length doesn't make sense, our only solution is
which is 3.860 to the nearest thousandth
Check:
Start with the given area function
plug in x=3.860
multiply
Add
Since we rounded, this is as close as it gets. So our answer is verified.