SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle? Thanks fo

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle? Thanks fo      Log On


   



Question 90292This question is from textbook Beginning Al
: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
Thanks for the help!
This question is from textbook Beginning Al

Answer by vertciel(183) About Me  (Show Source):
You can put this solution on YOUR website!
Hello there,
Denote:
Width = w
Length = 1 + w
A rectangle can form two isosceles triangles, so we can use the Pythagorean Theorem to find the length and width.
a^2 + b^2 = c^2
w^2 + (w + 1)^2 = 4^2
2w^2 + 2w + 1 = 16
2w^2 + 2w - 15 = 0
Find w, and plug them into the short equations for width and length. There you are.