SOLUTION: Good day I have something puzzling me for quite a while now Let't take an example In the quadratic equation 1. 72c2 + 24c - 16 The answer is (12c - 4) (6c + 4)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Good day I have something puzzling me for quite a while now Let't take an example In the quadratic equation 1. 72c2 + 24c - 16 The answer is (12c - 4) (6c + 4)       Log On


   



Question 901776: Good day
I have something puzzling me for quite a while now
Let't take an example
In the quadratic equation
1. 72c2 + 24c - 16
The answer is (12c - 4) (6c + 4)
Firstly.. Why 12 and 6? why not something like 9 and 8
Tried the formula with this example numbered as "1."
Secondly.. How do I know from the equation "72c2 + 24c - 16" which bracket is going to get the "+" and which bracket is going to get the "-"
They explained it in school but I just can't remember the principles.
Kind Regards.
Stefan.

Found 4 solutions by ewatrrr, MathTherapy, Alan3354, richwmiller:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
72c^2 + ++highlight_green%2824c%29+ - 16 = (12c - 4)(6c+4)
Why? Check with FOIL
F First terms 72c^2
O Outside terms 48c
I Inside terms -24c Note(48c-24c = ++highlight_green%2824c%29+ )
L Last terms -16

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Good day
I have something puzzling me for quite a while now
Let't take an example
In the quadratic equation
1. 72c2 + 24c - 16
The answer is (12c - 4) (6c + 4)
Firstly.. Why 12 and 6? why not something like 9 and 8
Tried the formula with this example numbered as "1."
Secondly.. How do I know from the equation "72c2 + 24c - 16" which bracket is going to get the "+" and which bracket is going to get the "-"
They explained it in school but I just can't remember the principles.
Kind Regards.
Stefan.

72c%5E2+%2B+24c+-+16
The first thing, when factoring this trinomial is to factor out the GCF, which is 8.
Thus, 72c%5E2+%2B+24c+-+16 becomes: 8%289c%5E2+%2B+3c+-+2%29, after which, 9c%5E2+%2B+3c+-+2 should be factored.
Final factors: highlight_green%288%283c+%2B+2%29%283c+-+1%29%29
It's confusing when c is the variable in the trinomial, so it's better to
change 72c%5E2+%2B+24c+-+16 to 72x%5E2+%2B+24x+-+16....same thing, just that the variable was changed from c to x.
Without factoring out a GCF, and applying the "ac" method, we would need two factors with a product
of - 1,152 (a * c, or 72 * - 16), and that SUM to "b" (+ 24). These factors are: + 48 and - 24.
We now replace + 24x in the trinomial, 72x%5E2+%2B+24x+-+16 with + 48x - 24x. I hope you're following!!
Now, 72x%5E2+%2B+24x+-+16 becomes: 72x%5E2+%2B+48x+-+24x+-+16. At this point, I'd switch the variable, x back to c,
so we now have: 72c%5E2+%2B+48c+-+24c+-+16
The factors are now obtained by grouping the first two binomials, and then the last two binomials, so that results in:
24c%283c+%2B+2%29+-+8%283c+%2B+2%29, and the final answer: %2824c+-+8%29%283c+%2B+2%29, which is the same as your factors: %2812c+-+4%29%286c+%2B+4%29.
Factoring these further, results in: highlight_green%288%283c+-+1%29%283c+%2B+2%29%29, the CORRECT factors.
However, %2824c+-+8%29%283c+%2B+2%29 and %2812c+-+4%29%286c+%2B+4%29 are incorrect as the GCF of the original polynomial should be obtained
and factored out first. I only went this far to explain the procedure to determine the correct factors when
leading-coefficient multiples such as 24, 36, 72, and others are part of polynomials that need to be factored.
These and other leading-coefficient multiples pose a problem at times since they have as many as 4 or 5 sets of
factors, and can be pretty tedious to factor correctly.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
In the quadratic equation
1. 72c2 + 24c - 16
---------------
That's not an equation, there's no equal sign.
The answer is (12c - 4) (6c + 4)
------------
I would say it's 8*(3c-1)*(3c+2)
-------
The short answer is, because 9 and 8 don't work. If you factor out the 8 first, it's obvious it can't be 9 and 8.
72c%5E2+%2B+24c+-+16+=+8%289c%5E2+%2B+3c+-+2%29
Then you might ask, "Why 3 and 3, and not 9 and 1?"
You can't get the middle term to be 3c using 9 and 1.
-------
Factor out any coefficients first, it'll make it simpler.
Use ^ (Shift 6) for exponents.
eg, c^2

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


72%2Ac%5E2%2B24%2Ac-16 Start with the given expression.



8%289c%5E2%2B3c-2%29 Factor out the GCF 8.



Now let's try to factor the inner expression 9c%5E2%2B3c-2



---------------------------------------------------------------



Looking at the expression 9c%5E2%2B3c-2, we can see that the first coefficient is 9, the second coefficient is 3, and the last term is -2.



Now multiply the first coefficient 9 by the last term -2 to get %289%29%28-2%29=-18.



Now the question is: what two whole numbers multiply to -18 (the previous product) and add to the second coefficient 3?



To find these two numbers, we need to list all of the factors of -18 (the previous product).



Factors of -18:

1,2,3,6,9,18

-1,-2,-3,-6,-9,-18



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -18.

1*(-18) = -18
2*(-9) = -18
3*(-6) = -18
(-1)*(18) = -18
(-2)*(9) = -18
(-3)*(6) = -18


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 3:



First NumberSecond NumberSum
1-181+(-18)=-17
2-92+(-9)=-7
3-63+(-6)=-3
-118-1+18=17
-29-2+9=7
-36-3+6=3




From the table, we can see that the two numbers -3 and 6 add to 3 (the middle coefficient).



So the two numbers -3 and 6 both multiply to -18 and add to 3



Now replace the middle term 3c with -3c%2B6c. Remember, -3 and 6 add to 3. So this shows us that -3c%2B6c=3c.



9c%5E2%2Bhighlight%28-3c%2B6c%29-2 Replace the second term 3c with -3c%2B6c.



%289c%5E2-3c%29%2B%286c-2%29 Group the terms into two pairs.



3c%283c-1%29%2B%286c-2%29 Factor out the GCF 3c from the first group.



3c%283c-1%29%2B2%283c-1%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%283c%2B2%29%283c-1%29 Combine like terms. Or factor out the common term 3c-1



--------------------------------------------------



So 8%289c%5E2%2B3c-2%29 then factors further to 8%283c%2B2%29%283c-1%29



===============================================================



Answer:



So 72%2Ac%5E2%2B24%2Ac-16 completely factors to 8%283c%2B2%29%283c-1%29.



In other words, 72%2Ac%5E2%2B24%2Ac-16=8%283c%2B2%29%283c-1%29.



Note: you can check the answer by expanding 8%283c%2B2%29%283c-1%29 to get 72%2Ac%5E2%2B24%2Ac-16 or by graphing the original expression and the answer (the two graphs should be identical).