SOLUTION: In a two digit number, the ten's digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number... Answer is given i.e. 93.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: In a two digit number, the ten's digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number... Answer is given i.e. 93.       Log On


   



Question 894032: In a two digit number, the ten's digit is bigger. The product of the digits is 27 and the difference between two digits is 6. Find the number...
Answer is given i.e. 93.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
n=10t+o
t>o
t*o=27
t-o=6
t=o+6
t*o=27
o*(o+6)=27
o^2+6o-27=0
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression o%5E2%2B6o-27, we can see that the first coefficient is 1, the second coefficient is 6, and the last term is -27.



Now multiply the first coefficient 1 by the last term -27 to get %281%29%28-27%29=-27.



Now the question is: what two whole numbers multiply to -27 (the previous product) and add to the second coefficient 6?



To find these two numbers, we need to list all of the factors of -27 (the previous product).



Factors of -27:

1,3,9,27

-1,-3,-9,-27



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -27.

1*(-27) = -27
3*(-9) = -27
(-1)*(27) = -27
(-3)*(9) = -27


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 6:



First NumberSecond NumberSum
1-271+(-27)=-26
3-93+(-9)=-6
-127-1+27=26
-39-3+9=6




From the table, we can see that the two numbers -3 and 9 add to 6 (the middle coefficient).



So the two numbers -3 and 9 both multiply to -27 and add to 6



Now replace the middle term 6o with -3o%2B9o. Remember, -3 and 9 add to 6. So this shows us that -3o%2B9o=6o.



o%5E2%2Bhighlight%28-3o%2B9o%29-27 Replace the second term 6o with -3o%2B9o.



%28o%5E2-3o%29%2B%289o-27%29 Group the terms into two pairs.



o%28o-3%29%2B%289o-27%29 Factor out the GCF o from the first group.



o%28o-3%29%2B9%28o-3%29 Factor out 9 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28o%2B9%29%28o-3%29 Combine like terms. Or factor out the common term o-3



===============================================================



Answer:



So o%5E2%2B6%2Ao-27 factors to %28o%2B9%29%28o-3%29.



In other words, o%5E2%2B6%2Ao-27=%28o%2B9%29%28o-3%29.



Note: you can check the answer by expanding %28o%2B9%29%28o-3%29 to get o%5E2%2B6%2Ao-27 or by graphing the original expression and the answer (the two graphs should be identical).



o=3
t-3=6
t=9
n=93