the first graph doesn't allow values of x = 1 because that would make the denominator equal to 0 and the function would be undefined.
the first graph also doesn't allow values of x <1 because that would make the numerator the squart root of a negative number which is also undefined in the real number system.
the second graph goes to 0 because x+1 will be positive for values less than 1 of x but greater than or equal to 0 and will also allows x = 1 because there is no denominator in that equation.
the 2 equations are equivalent except that once you eliminated the denominator by canceling it out, you can then get a defined solution at x = 1.