SOLUTION: How do you translate y=-2x^2+16x-27 to vertex form if the vertex is (4,5)? And how would you translate y=4x^2+8x+1 to vertex form if the vertex is (-1,-3)?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: How do you translate y=-2x^2+16x-27 to vertex form if the vertex is (4,5)? And how would you translate y=4x^2+8x+1 to vertex form if the vertex is (-1,-3)?       Log On


   

Question 878178: How do you translate y=-2x^2+16x-27 to vertex form if the vertex is (4,5)? And how would you translate y=4x^2+8x+1 to vertex form if the vertex is (-1,-3)?
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
This response assumes that the vertices you report are the correct one for each equation.

You would rely on knowledge of the standard form equation for a parabola.
y=a%28x-h%29%5E2%2Bk has vertex (h,k). The transformation between general and standard forms would not change to "a" variable. This will be the same variable or number as found on the leading term of general form.

y=-2x%5E2%2B16x-27, if vertex (4,5) should be y=-2%28x-4%29%5E2%2B5;

y=4x%5E2%2B8x%2B1, if vertex (-1,-3) should be y=4%28x%2B1%29%5E2-3.