Let
Then
So substitute for
and for
6u - 13 = 0; 2u - 5 = 0
6u = 13 2u = 5
u = u =
For u = , since
Multiply through by 6x
(3x-2)(2x-3) = 0
3x-2 = 0; 2x-3 = 0
3x = 2; 2x = 3
x = ; x =
------
For u = , since
Multiply through by 2x
(2x-1)(x-2) = 0
2x-1 = 0; x-2 = 0
2x = 1; x = 2
x = ;
So there are four solutions:
x =
x =
x =
x = 2
Edwin