SOLUTION: find the vertex and x-intercept(s) of the function given below y=x^2-x-23

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Question 873666: find the vertex and x-intercept(s) of the function given below y=x^2-x-23
Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2-x-23
y = (x - 1/2)^2 -1/4 - 23
y = (x - 1/2)^2 - 93/4 V(1/2, -93/4)
0 = (x - 1/2)^2 - 93/4
+1%2F2+%2B-sqrt%2893%29%2F2%29+ = x

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square,
y=x%5E2-x-23
y=%28x%5E2-x%2B1%2F4%29-23-1%2F4
y=%28x-1%2F2%29%5E2-92%2F4-1%2F4
y=%28x-1%2F2%29%5E2-93%2F4
The vertex is (1/2,-93/4).
0=%28x-1%2F2%29%5E2-93%2F4
%28x-1%2F2%29%5E2=93%2F4
x-1%2F2=0+%2B-+sqrt%2893%29%2F2
x=1%2F2+%2B-+sqrt%2893%29%2F2