Question 86373: x-[3x-2(9-x)]-1< x-(5-x) Please help me I am mathematically challenged!!Answer by Edwin McCravy(8999)   (Show Source): You can put this solution on YOUR website!``` x - [3x - 2(9 - x)] - 1 < x - (5 - x) Multiply the - 2 by the 9 and write - 18 Multiply the - 2 by the - x and write + 2x x - [3x - 18 + 2x] - 1 < x - (5 - x) Combine the 3x and the + 2x and write 5x x - [5x - 18] - 1 < x - (5 - x) Put a 1 just before the bracket on the left and a 1 just before the parentheses on the right: x - 1[5x - 18] - 1 < x - 1(5 - x) Multiply the - 1 by the 5x and write - 5x Multiply the - 1 by the - 18 and write + 18 Multiply the - 1 by the 5 and write - 5 Multiply the - 1 by the - x and write + x x - 5x + 18 - 1 < x - 5 + x Combine the x and the - 5x and write -4x Combine the + 18 and the - 1 and write + 17 On the right, combine the x and the + x and write 2x -4x + 17 < 2x - 5 Add -17 to both sides -4x < 2x - 22 Add -2x to both sides: -6x < -22 Divide both sides by -6, remembering that when you divide an inequality by a negative number, the inequality is reversed: > x > Edwin```