SOLUTION: Solve by completing the square... 1.x^2+4x+3=0 2.x^2=5x+2 3.2x^2-8x-9=0 4.4x^2+2x-3=0 Thanks in advance for all of your help!!!

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve by completing the square... 1.x^2+4x+3=0 2.x^2=5x+2 3.2x^2-8x-9=0 4.4x^2+2x-3=0 Thanks in advance for all of your help!!!      Log On


   



Question 86121: Solve by completing the square...
1.x^2+4x+3=0
2.x^2=5x+2
3.2x^2-8x-9=0
4.4x^2+2x-3=0
Thanks in advance for all of your help!!!

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve by completing the square:
1)
x%5E2%2B4x%2B3+=+0 First, subtract 3 from both sides.
x%5E2%2B4x+=+-3 Now complete the square in the x-terms by adding the square of half the x-coefficient (that's the 4) to both sides...so you'll be adding %284%2F2%29%5E2+=+4 to both sides.
x%5E2%2B4x%2B4+=+-3%2B4 Simplify.
x%5E2%2B4x%2B4+=+1 Now factor the left side.
%28x%2B2%29%28x%2B2%29+=+1 Rewrite this as:
%28x%2B2%29%5E2+=+1 Now take the square root of both sides.
x%2B2+=+1 or x%2B2+=+-1 Finally, subtract 2 from both sides of each equation.
x+=+-1 or x+=+-3
2)
x%5E2+=+5x%2B2 Subtract 5x from both sides.
x%5E2-5x+=+2 Complete the square in the x-terms by adding the square of half the x-coeffient (that's the -5) to both sides....so you'll be adding %28-5%2F2%29%5E2+=+25%2F4 to both sides.
x%5E2-5x%2B%2825%2F4%29+=+2%2B%2825%2F4%29 Simplify.
x%5E2-5x%2B%2825%2F4%29+=+33%2F4 Now factor the left side.
%28x-%285%2F2%29%29%28x-%285%2F2%29%29+=+33%2F4 Rewrite this as:
%28x-%285%2F2%29%29%5E2+=+33%2F4 Now take the square root of both sides.
x-%285%2F2%29+=+sqrt%2833%29%2F2 or x-%285%2F2%29+=+-sqrt%2833%29%2F2 Add 5%2F2 to both sides of each equation.
x+=+%285%2F2%29%2Bsqrt%2833%29%2F2 or x+=+%285%2F2%29-sqrt%2833%29%2F2 Simplify.
x+=+%285%2Bsqrt%2833%29%29%2F2 or x+=+%285-sqrt%2833%29%29%2F2
3)
2x%5E2-8x-9+=+0 First, you need to make the coefficient of x%5E2 equal to 1 and you can do this simply by dividing everything by 2.
x%5E2-4x-%289%2F2%29+=+0 Now you'll proceed as above, add %289%2F2%29 to both sides.
x%5E2-4x+=+%289%2F2%29 Complete the square in the x-terms by adding the square of half the x-coefficient to both sides.
x%5E2-4x%2B4+=+%289%2F2%29%2B4 Simplify.
x%5E2-4x%2B4+=+17%2F2 Now factor the left side.
%28x-2%29%5E2+=+17%2F2 Take the square root of both sides.
x-2+=+sqrt%2817%2F2%29 or x-2+=+-sqrt%2817%2F2%29 Now add 2 to both sides of each equation.
x+=+2%2Bsqrt%2817%2F2%29 or x+=+2-sqrt%2817%2F2%29
This should give you a good idea on how to do the remaining problem.
The answers are:
x+=+%28-1%2Bsqrt%2813%29%29%2F4
x+=+%28-1-sqrt%2813%29%29%2F4